From The Reaction: B2h6 + O2 Hbo2 + H2o A. What Mass Of O2 Will Be Needed To Burn 36.1 G Of B2h6? B. How Many Moles Of Water Are Produced From 19.2 G

From the reaction: B2H6 + O2 HBO2 + H2O a. What mass of O2 will be needed to burn 36.1 g of B2H6? b. How many moles of water are produced from 19.2 g of B2H6?

 

Answer:

a.) The mass of O₂ that will be needed to burn 36.1 g B₂H₆ is 125.29 g.

b.) There will be 1.39 moles of water produced from 19.2 g of B₂H₆.

Explanation:

This problem is an application of stoichiometry. Stoichiometry is a topic of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data or value.

In our case, the quantitative date we want is the a.) mass of oxygen (O₂) and b.) moles of water (H₂O) both from the reaction of diborane (B₂H₆) and oxygen (O₂).

Stoichiometry problems always need a balanced chemical reaction. In the problem, the chemical reaction is not yet balanced, meaning, we still need to balance the chemical equation reaction.

Balancing the chemical reaction we have:

B₂H₆ + O₂ → HBO₂ + H₂O

B₂H₆ + 3 O₂ → 2 HBO₂ + 2 H₂O

From the balanced chemical equation there are 2 moles of water forming from 1 mole of diborane, and 3 moles of oxygen is needed to react with 1 mole of diborane. These facts are to be used in order to solve the problem.

a.) Solving for the mass of oxygen from 36.1 grams of B₂H₆, we have:

(36.1 g B₂H₆) (\frac{1 mol B2H6}{27.66 g B2H6}) (\frac{3 mol O2}{1 mol B2H6}) (\frac{32 grams O2}{1 mol O2} ) = 125.29 grams O₂

b.) Solving for moles of water from 19.2 grams of diborane, we have:

(19.2 g B₂H₆) (\frac{1 mol B2H6}{27.66 g B2H6}) = 1.39 mol H₂O

Note: 27.66 g B₂H₆ is from the molar mass of diboran, and 32 g/mole is from the molar mass of oxygen; these are necessary to use in order to cancel the units.

Hence, a.) There are 125.29 grams of O₂ needed to burn 36.1 g of B₂H₆, and b.) there will be 1.39 moles of water produced from 19.2 grams of B₂H₆.

To read more information about chemical equations, click here: brainly.ph/question/2133024

To learn more about stoichiometry, click here: brainly.ph/question/86627

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