What Is The Quotient (3x4 2013 4x2 + 8x 2013 1) \Xf7 (X 2013 2)?

What is the quotient (3x4 – 4x2 + 8x – 1) ÷ (x – 2)?

Answer:

3x^{3} +6x^{2} +8x + 24 +\frac{47}{x-2}

Step-by-step explanation:

I used synthetic division here.

So first get the constant of the denominator which is -2 and change the reverse the sign, so it will become 2.

Next get all the coefficients of the numerator. Which are:

3, 0, -4, 8, and -1

Notice that the exponent from the equation doesnt have x^{3} so it will become 0. It is called missing term.

Now, lets solve.

First, separate the constant of the denominator by drawing a line or box.

Then align the coefficients of the numerator.

The operation will be addition.

It looks like this:

2I     3    0    -4    8    -1

+

Now bring down the first number which is 3. (You will not bring down the 2, because it will be used for multiplication.)

2I     3    0    -4    8    -1

+

        3

Then multiply it by the constant of the denominator which is 2,

2I     3    0    -4    8    -1

+             6

        3

Then add,

2I     3    0    -4    8    -1

+             6

        3    6

Next multiply the product and add it to the next term. Repeat it until you last the last number.

2I     3       0       -4       8       -1

+                6       12      16     48

        3       6       8       24     47

The last number will be the remainder.

Now lets subtract the exponent with 1. And substitute the new coefficient.

3x^{3} +6x^{2} +8x + 24

As I said "the last term will be remainder."

You can write r. 47 or \frac{47}{x-2} (it has x-2 because it is not divisible)

So the final answer is:

3x^{3} +6x^{2} +8x + 24 +\frac{47}{x-2}


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