Which Of The Following Is An, Alkali Metals?, ?, A. Hydrogen, B. Potassium, C. Silicon, D. Zinc

Which of the following is an

alkali metals?
?
a. Hydrogen
b. potassium
c. Silicon
d. Zinc

 

Answer:

B. Potassium

Explanation:

Alkali metals are found in the first column of the periodic table (disregarding Hydrogen of course since it is a non-metal and its placement in the table is unique)


Comments

Post a Comment

Popular posts from this blog

Which Species Is Most Likely To Exhibit Clumped Dispersion?, A. , Dandelions With Seeds Dispersed By The Wind, B. , Tigers That Defend Their Territori

Which species is most likely to exhibit clumped dispersion? A. dandelions with seeds dispersed by the wind B. tigers that defend their territories from one another C. a bird that nests in many different types of trees D. a tree that grows only on the banks of streams   Which species is most likely to exhibit clumped dispersion? A.dandelions with seeds dispersed by the wind B.tigers that defend their territories from one another C.a bird that nests in many different types of trees D.a tree that grows only on the banks of streams The answer is letter B.  tigers that defend their territories from one another. Here are the explanation. Clumped dispersion is when there is a clustering of individuals in a  group, producing some patches with several individuals and some patches with no individuals.   Individuals are spaced evenly across  an area, in uniform dispersion.  And the individuals are distributed in  random dispersion without any apparent pattern. ...
Read more

9. What Is The 6th Term Of The Geometric Sequence 2/25, 2/5, 2, 10,2026?, A. 25 , B. 250 , C. 1250 , D. 2500

9. What is the 6th term of the geometric sequence 2/25, 2/5, 2, 10,…? a. 25 b. 250 c. 1250 d. 2500   Geometric Sequence The 6th term of the geometric sequence 2/25, 2/5, 2, 10 ,.... is 250. Solution: Geometric Sequence Formula: a_n = a₁r ⁿ ⁻ ¹ Given: a₁ = 2/25           a₂ = 2/5           a₃ = 2           a₄ = 10 1. Find the common ratio.        a_n = a₁r ⁿ ⁻ ¹         a₂  = a₁r ⁿ ⁻ ¹        2/5 = 2/25 r  ² ⁻ ¹        2/5 = 2/25 r 2. Divide both sides of the equation by 2/25 to find r.     2/5/2/25 = 2/25 r/2/25   (2/5)(25/2) = r           50/10 = r                  5 = r 3. Using r = 5, find the 6th term of the geometric sequence.             a_n = a₁r ⁿ ⁻ ¹               a₆ = a₁r ⁿ ⁻ ¹               a₆ = 2/25(5) ⁶ ⁻ ¹               a₆ = 2/25 (5)⁵               a₆ = 2/25 (3, 125)               a₆ = 6, 250/25              a₆ = 250 4. Therefore, the 6th term of the geometric sequence 2/25, 2/5, 2, 10… .is 250. Definition: ...
Read more