(2by)\Xb3 For Y=-2 Leaving B As Constant

(2by)³ for y=-2 leaving b as constant

 

Answer:

-64b³

Step-by-step explanation:

(2by)³; y = -2

((2b(-2))³

(8b³)(-8)

= -64b³


Comments

Post a Comment

Popular posts from this blog

What Is The Nature Of The Teenager2019s Problem?

What is the nature of the teenager's problem?   Answer: Usually, the teenagers behavior is doesnt care the results of their decision. They dont even matter the things they bought or sold as long as they enjoy it very much. The nature of them is looking for their enjoyable experience that does not think whether it has a good outcome in their lives or not. Explanation: Teenagers behavioral actions are as follows: 1. They will only regret when they experience the bad effect of the decision theyve made. 2. Teenagers are effortless also because theyre not mature enough for the responsibilities of life.   3. They dont know yet how to settle things in order or even control themselves from making the wrong actions which later may result for sadness.   But this is not addressed to all teenagers because some of the teenagers to are matured enough to face and handle their problems. It depends on how the way their parents raised them or others raised without the guidance from their pa...
Read more

What Is The Quotient (3x4 2013 4x2 + 8x 2013 1) \Xf7 (X 2013 2)?

Image
What is the quotient (3x4 – 4x2 + 8x – 1) ÷ (x – 2)?   Answer: Step-by-step explanation: I used synthetic division here. So first get the constant of the denominator which is -2 and change the reverse the sign, so it will become 2. Next get all the coefficients of the numerator. Which are: 3, 0, -4, 8, and -1 Notice that the exponent from the equation doesnt have so it will become 0. It is called missing term. Now, lets solve. First, separate the constant of the denominator by drawing a line or box. Then align the coefficients of the numerator. The operation will be addition. It looks like this: 2I     3    0    -4    8    -1 + Now bring down the first number which is 3. (You will not bring down the 2, because it will be used for multiplication.) 2I     3    0    -4    8    -1 +         3 Then multiply it by the constant of the denominator which is 2, 2I     3    0    -4    8    -1 +             6         3 Then add, 2I     3    0    -4    8    -1 +             6         3...
Read more